(4x^2+16x+17)/(x+3)

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Solution for (4x^2+16x+17)/(x+3) equation: 


D( x )

x+3 = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:+oo)

(4*x^2+16*x+17)/(x+3) = 0

4*x^2+16*x+17 = 0

4*x^2+16*x+17 = 0

DELTA = 16^2-(4*4*17)

DELTA = -16

DELTA < 0

1 = 0

1/(x+3) = 0

x belongs to the empty set

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